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0=2x^2+5x+10
We move all terms to the left:
0-(2x^2+5x+10)=0
We add all the numbers together, and all the variables
-(2x^2+5x+10)=0
We get rid of parentheses
-2x^2-5x-10=0
a = -2; b = -5; c = -10;
Δ = b2-4ac
Δ = -52-4·(-2)·(-10)
Δ = -55
Delta is less than zero, so there is no solution for the equation
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